In alcohols, the oxygen of the -OH group is attached to sp3 hybridised carbon by a sigma bond formed by the overlap of sp3 hybrid orbital of carbon with an sp3 hybrid orbital of oxygen. The figure shown below illustrates the bonding in methanol.
The C-O-H bond angle in alcohol is slightly less than the tetrahedral angle (109028). It is due to the repulsion between the unshared electron pairs of oxygen.
In phenols, the –OH group is attached to sp2 hybrid carbon of an aromatic ring. The C-O-H bond angle in phenol is 1090. The carbon-oxygen bond length (136pm) in phenol is slightly less than that in methanol (142pm). This is due to partial double bond character on account of the conjugation of unshared electron pair of oxygen with the aromatic ring.
In ethers, the four electron pairs, ie; the two bond pairs and two lone pairs of electrons around oxygen are arranged approximately in a tetrahedral arrangement. The c-o-c bond angle (111.70 in methoxy methane) is slightly greater than the tetrahedral angle (109028) due to the repulsive C-O bond length (141 pm) in ethers is almost the same as in alcohols (142 pm in methanol).
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pH of Buffer solution
The pH of acidic and basic buffer can be calculated by Henderson – Hasselbalch equations. Consider an acidic buffer HA + A-
HA <=======> H+ + A-
Ka = [H+] [A-] / [HA]
[H+] = Ka [HA]/[A-]
[H+] = Ka [acid]/[salt]
There fore pH = -log[H+]
pH = pKa + log [salt]/[acid]
when, [salt]/[acid] = 1 ,
pH = pKa
Since pKa of an acid is a constant at constant temperature, the pH of the buffer is constant. Thus buffer capacity is maximum in a solution containing equivalent amount of acid and its salt.
The pH of basic buffer is also given by Henderson – Hasselbalch equation
BOH <=======> B+ + OH-
Kb = [B+][OH-]/[BOH]
[OH-] = Kb [BOH]/[B+]
pOH = pKb + log [salt]/[base]
pH = 14 – pOH
= 14 – [pKb + log [salt]/[base]]
HA <=======> H+ + A-
Ka = [H+] [A-] / [HA]
[H+] = Ka [HA]/[A-]
[H+] = Ka [acid]/[salt]
There fore pH = -log[H+]
pH = pKa + log [salt]/[acid]
when, [salt]/[acid] = 1 ,
pH = pKa
Since pKa of an acid is a constant at constant temperature, the pH of the buffer is constant. Thus buffer capacity is maximum in a solution containing equivalent amount of acid and its salt.
The pH of basic buffer is also given by Henderson – Hasselbalch equation
BOH <=======> B+ + OH-
Kb = [B+][OH-]/[BOH]
[OH-] = Kb [BOH]/[B+]
pOH = pKb + log [salt]/[base]
pH = 14 – pOH
= 14 – [pKb + log [salt]/[base]]
Buffer action
The property of a buffer solution to resist change in its pH value even when small amounts of the acid or the base are added to it is called buffer action.
Consider the acidic buffer solution containing acetic acid and sodium acetate. They dissociate as
CH3COONa <=======> CH3COO- + H+
CH3COONa <=======> CH3COO- + Na+
When a few drops of an acid, HCl is added to this buffer solution, the H+ ions combine with CH3COO- ions to form weakly ionized molecules of CH3COOH.
CH3COO- + H+ <=======> CH3COOH
Thus H+ ion concentration does not change and hence the pH of the solution remains constant.
When a few drops of base, NaOH is added to the buffer solution, hydroxyl ions of the base neutralize the acid, forming salt and water.
Similarly, in a basic buffer solution of NH4OH and NH4Cl, they dissociates as
NH4OH <======> NH4+ + OH-
NH4Cl ----------> NH4+ + Cl-
When a few drops of a base added, the OH- ions given by it combine with NH4+ ions to form the weakly ionized NH4OH.
NH4+ + OH- ---------> NH4OH
Thus the OH- ion concentration or the pH of the solution remains unaffected.
When a small amount of an acid is added, the H+ ions given by it combines with the OH- ions already produced by NH4OH.
H+ + OH- --------> H2O
Therefore the H+ ions concentration or the pH of the solution remains unaffected.
The buffer capacity of a buffer solution is defined as the number of moles of acid or base added per liter of the solution to change the pH by one unit.
Consider the acidic buffer solution containing acetic acid and sodium acetate. They dissociate as
CH3COONa <=======> CH3COO- + H+
CH3COONa <=======> CH3COO- + Na+
When a few drops of an acid, HCl is added to this buffer solution, the H+ ions combine with CH3COO- ions to form weakly ionized molecules of CH3COOH.
CH3COO- + H+ <=======> CH3COOH
Thus H+ ion concentration does not change and hence the pH of the solution remains constant.
When a few drops of base, NaOH is added to the buffer solution, hydroxyl ions of the base neutralize the acid, forming salt and water.
Similarly, in a basic buffer solution of NH4OH and NH4Cl, they dissociates as
NH4OH <======> NH4+ + OH-
NH4Cl ----------> NH4+ + Cl-
When a few drops of a base added, the OH- ions given by it combine with NH4+ ions to form the weakly ionized NH4OH.
NH4+ + OH- ---------> NH4OH
Thus the OH- ion concentration or the pH of the solution remains unaffected.
When a small amount of an acid is added, the H+ ions given by it combines with the OH- ions already produced by NH4OH.
H+ + OH- --------> H2O
Therefore the H+ ions concentration or the pH of the solution remains unaffected.
The buffer capacity of a buffer solution is defined as the number of moles of acid or base added per liter of the solution to change the pH by one unit.
Buffer solutions
Maintenance of PH in blood and in intracellular fluids is absolutely crucial to the processes that occur in living organisms. This is primarily because the functioning of enzymes is sharply pH dependent. The normal pH value of blood plasma is 7.4 and several illness or death can result from sustained variations of a few tenths of pH unit. Also many medical and cosmetic formulations require that these must be kept and administered at a particular pH. There are solutions which resist the change in pH on addition of small amount of acid or alkali and are called Buffer solution. For example a mixture of H2CO3 and HCO3- is a natural buffer system which maintains the pH of blood. A buffer that is widely used in clinical laboratory and in biochemical studies in the physiological pH range is prepared from tris amino methane (hydroxy methyl) (THAM) [(HOCH2)3CNH2].
In order for a solution to act as a buffer it must have two components, one of which is able to neutralize acid and the other able to neutralize the base. Common buffer solutions are mixtures containing a
Weak acid and its conjugate base (one of its salt) called acidic buffer
eg:- CH3OOH/CH3COONa, H2CO3/Na2CO3, Boric acid/borax
Weak base and its conjugate acid (one of its salt) called basic buffer
Eg:- NH4OH/NH4Cl, Zinc hydroxide/ zinc chloride, Glycine/ glycine hydrochloride.
In order for a solution to act as a buffer it must have two components, one of which is able to neutralize acid and the other able to neutralize the base. Common buffer solutions are mixtures containing a
Weak acid and its conjugate base (one of its salt) called acidic buffer
eg:- CH3OOH/CH3COONa, H2CO3/Na2CO3, Boric acid/borax
Weak base and its conjugate acid (one of its salt) called basic buffer
Eg:- NH4OH/NH4Cl, Zinc hydroxide/ zinc chloride, Glycine/ glycine hydrochloride.
Application of solubility product and common ion effect
Qualitative analysis of cations is largely based on the principle of solubility product and common ion effect. Cations are separated in to six groups depending on the solubility of their salts.
Group-1 as insoluble chlorides
Only Ag+, Hg2+ and Pb2+ form insoluble chlorides since they have low values of Ksp.
Group-2 as insoluble sulphide in acidic medium
H2S <========> H+ + HS- ;
K1 - first ionization constant
HS- <========> H+ + S2-;
K2 – second ionization constant
[S2-] = K1K2 [H2S]/[H+]2
Ksp values of second group sulphides (PbS, CuS, SnS, HgS, As2S3, Bi2S3, Sb2S3) are very low. In acidic buffer, [S2-] is decreased due to common ion effect and this results in the precipitation of Pb2+, Cu2+ etc of second group as their sulphides. Third and fourth group sulphides have high value of Ksp, hence they remain soluble.
Group- 3 as insoluble hydroxide in basic buffer of NH4OH and NH4Cl
The concentration of OH- in ammoniacal solution decreases when NH4Cl is added to it, because of the common ion effect. Thus only for least soluble hydroxide of Fe3+, Al3+, Cr3+ etc. ionic product exceeds the corresponding solubility products, hence only these ions are precipitated. Hydroxides of successive remain soluble due to high Ksp values.
Group-1 as insoluble chlorides
Only Ag+, Hg2+ and Pb2+ form insoluble chlorides since they have low values of Ksp.
Group-2 as insoluble sulphide in acidic medium
H2S <========> H+ + HS- ;
K1 - first ionization constant
HS- <========> H+ + S2-;
K2 – second ionization constant
[S2-] = K1K2 [H2S]/[H+]2
Ksp values of second group sulphides (PbS, CuS, SnS, HgS, As2S3, Bi2S3, Sb2S3) are very low. In acidic buffer, [S2-] is decreased due to common ion effect and this results in the precipitation of Pb2+, Cu2+ etc of second group as their sulphides. Third and fourth group sulphides have high value of Ksp, hence they remain soluble.
Group- 3 as insoluble hydroxide in basic buffer of NH4OH and NH4Cl
The concentration of OH- in ammoniacal solution decreases when NH4Cl is added to it, because of the common ion effect. Thus only for least soluble hydroxide of Fe3+, Al3+, Cr3+ etc. ionic product exceeds the corresponding solubility products, hence only these ions are precipitated. Hydroxides of successive remain soluble due to high Ksp values.
The solubility product constant (Ksp)
The solubilityof ionic solids in water varies depending on a number of factors like lattice enthalpy of the salt and tha solvation enthalpy of the ions in a solution. As a general rule, for a salt to be able to dissolve in a particular solvent, its solvation enthalpy must be greater than its lattice enthalpy. Each salt has its characteristic solubility, which depends on temperature. We can classify salts on the basis of their solubility in three categories.
Soluble - Solubility > 0.1 M
Slightly soluble - 0.01 M < solubility < 0.1M
Sparingly soluble – solubility < 0.01M
We have now consider the equilibrium between the sparingly soluble ionic salt and its saturated aqueous solution. A solution which remains in contact with excess of the solute is said to be saturated. The amount of a solvent () in 100 ml or 1L) to form a saturated solution at a given temperature is termed as the solubility of the solute in the solvent at that temperature.
For a sparingly soluble salts like AgCl,PbI2, BaSO4 etc. Ionisation is very small and concentration of the salt may be considered as constant. Thus, for AgCl,
AgCl <========> Ag+ + Cl-
K = [Ag+][Cl-]/[AgCl]
For a pure solid substance the concentration remains constant and we can write
Ksp = K[AgCl]
=[Ag+][Cl-]
Where Ksp is the solubility product constant or solubility product.
If S represents solubility of AgCl (in mol L-1)
Then [Ag+]= [Cl-] = S molL-1
Ksp = [Ag+][cl-] = S2
S = √Ksp
A solubility product constant expression is the product of the chemical equation for a solubility equilibrium, with each term raised to the power given by the coefficient in the chemical equation.
Example:-
For BaSO4 (binary solute giving two ions)
BaSO4 <=======> Ba2++ SO42-
Ksp = [Ba2+][SO42-] = S2
For PbI2 (Ternary solute giving three ions)
PbI2 <=======> Pb2+ + 2I-
Ksp = [Pb2+][I-]2 = (s)(2s)2 = 4S3
For Al(OH)3 (Quaternary solute giving four ions)
Al(OH)3 <=======> Al3+ + 3OH-
Ksp = [Al3+][OH-]3 = (S)(3S)3 = 27Ss4
For a solute AxBy, (giving (x+y) ions)
Ksp = [Ay+]x [Bx-]y = (xS)x (yS)y = XxYy(S)(x+y)
Precipitation reactions
For the sparingly soluble solute AB,
AB <=======> A+ +B-
Q is the equilibrium constant with the given [A+] and [B-]
Q = [A+][B-]
When applied to solubility product, Q is generally called the ionic product. Precipitation occurs if Q>Ksp, then solution is said to be super saturated and precipitation cannot occur if Qsp (a case of unsaturated solution) and a solution is just saturated if Q=Ksp.
Soluble - Solubility > 0.1 M
Slightly soluble - 0.01 M < solubility < 0.1M
Sparingly soluble – solubility < 0.01M
We have now consider the equilibrium between the sparingly soluble ionic salt and its saturated aqueous solution. A solution which remains in contact with excess of the solute is said to be saturated. The amount of a solvent () in 100 ml or 1L) to form a saturated solution at a given temperature is termed as the solubility of the solute in the solvent at that temperature.
For a sparingly soluble salts like AgCl,PbI2, BaSO4 etc. Ionisation is very small and concentration of the salt may be considered as constant. Thus, for AgCl,
AgCl <========> Ag+ + Cl-
K = [Ag+][Cl-]/[AgCl]
For a pure solid substance the concentration remains constant and we can write
Ksp = K[AgCl]
=[Ag+][Cl-]
Where Ksp is the solubility product constant or solubility product.
If S represents solubility of AgCl (in mol L-1)
Then [Ag+]= [Cl-] = S molL-1
Ksp = [Ag+][cl-] = S2
S = √Ksp
A solubility product constant expression is the product of the chemical equation for a solubility equilibrium, with each term raised to the power given by the coefficient in the chemical equation.
Example:-
For BaSO4 (binary solute giving two ions)
BaSO4 <=======> Ba2++ SO42-
Ksp = [Ba2+][SO42-] = S2
For PbI2 (Ternary solute giving three ions)
PbI2 <=======> Pb2+ + 2I-
Ksp = [Pb2+][I-]2 = (s)(2s)2 = 4S3
For Al(OH)3 (Quaternary solute giving four ions)
Al(OH)3 <=======> Al3+ + 3OH-
Ksp = [Al3+][OH-]3 = (S)(3S)3 = 27Ss4
For a solute AxBy, (giving (x+y) ions)
Ksp = [Ay+]x [Bx-]y = (xS)x (yS)y = XxYy(S)(x+y)
Precipitation reactions
For the sparingly soluble solute AB,
AB <=======> A+ +B-
Q is the equilibrium constant with the given [A+] and [B-]
Q = [A+][B-]
When applied to solubility product, Q is generally called the ionic product. Precipitation occurs if Q>Ksp, then solution is said to be super saturated and precipitation cannot occur if Q
Common ion effect
The decrease in the ionization of a weak electrolyte by the presence of a common-ion from a strong electrolyte, is called the common ion effect. Ionisation of CH3COOH (weak acid) is decreased by the addition of CH3COONa (CH3COO- being the common ion)
CH3COOH <======> CH3COO- + H+ ………………………..(A)
CH3COONa -----------> CH3COO- + Na+
In the presence of CH3COO- equilibrium (A) shifts in backward direction.
Ionisation of H2S (weak acid) is decreased by the addition of HCl (H+ being the common ion)
H2S <=======> 2H+ + s2-
HCl <=======> H+ + Cl-
Ionisation of NH4OH (weak base) is decreased by the addition of NH4Cl (NH4 + being the common ion)
NH4OH <=======> NH4+ + OH-
NH4Cl --------------> NH4+ + Cl-
Solubility of a sparingly soluble salt is decreased by the addition of common ion. Presence of AgNO3 or KCl decreases the solubility of AgCl.
AgCl <=======> Ag+ + Cl-
AgNO3 <========> Ag+ (common ion) + NO3-
KCl <=======> K+ + Cl-(common ion)
The common ion effect is thus based on Le-Chatelier’s principle in which the stress on the equilibrium that results from raising one of the product concentrations is relieved by shifting the equilibrium to left.
CH3COOH <======> CH3COO- + H+ ………………………..(A)
CH3COONa -----------> CH3COO- + Na+
In the presence of CH3COO- equilibrium (A) shifts in backward direction.
Ionisation of H2S (weak acid) is decreased by the addition of HCl (H+ being the common ion)
H2S <=======> 2H+ + s2-
HCl <=======> H+ + Cl-
Ionisation of NH4OH (weak base) is decreased by the addition of NH4Cl (NH4 + being the common ion)
NH4OH <=======> NH4+ + OH-
NH4Cl --------------> NH4+ + Cl-
Solubility of a sparingly soluble salt is decreased by the addition of common ion. Presence of AgNO3 or KCl decreases the solubility of AgCl.
AgCl <=======> Ag+ + Cl-
AgNO3 <========> Ag+ (common ion) + NO3-
KCl <=======> K+ + Cl-(common ion)
The common ion effect is thus based on Le-Chatelier’s principle in which the stress on the equilibrium that results from raising one of the product concentrations is relieved by shifting the equilibrium to left.
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